Difference between revisions of "Derivative of arccoth"
From specialfunctionswiki
(Created page with "==Theorem== The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}z} \mathrm{arccoth}(z) = \dfrac{1}{z^2-1}.$$ ==Proof== ==References== Category:Theorem Categor...") |
|||
| Line 1: | Line 1: | ||
==Theorem== | ==Theorem== | ||
The following formula holds: | The following formula holds: | ||
| − | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \mathrm{arccoth}(z) = \dfrac{1}{z^2-1} | + | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \mathrm{arccoth}(z) = \dfrac{1}{z^2-1},$$ |
| + | where $\mathrm{arccoth}$ denote the [[arccoth|inverse hyperbolic cotangent]]. | ||
==Proof== | ==Proof== | ||
Revision as of 01:36, 16 September 2016
Theorem
The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}z} \mathrm{arccoth}(z) = \dfrac{1}{z^2-1},$$ where $\mathrm{arccoth}$ denote the inverse hyperbolic cotangent.
