Difference between revisions of "1/q-number as a q-number"
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Revision as of 08:02, 18 December 2016
Theorem
The following formula holds: $$[a]_{\frac{1}{q}}=q^{-a+1}[a]_q,$$ where $[a]_{\frac{1}{q}}$ denotes a $q$-number.