Difference between revisions of "Dawson D+"
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(Created page with "The Dawson function $D+$ is defined by $$D_+(x)=e^{-x^2}\displaystyle\int_0^x e^{t^2} dt,$$ where $e^{-x^2}$ denotes the exponential. =Properties= =References= Catego...") |
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Revision as of 06:55, 10 January 2017
The Dawson function $D+$ is defined by $$D_+(x)=e^{-x^2}\displaystyle\int_0^x e^{t^2} dt,$$ where $e^{-x^2}$ denotes the exponential.