Difference between revisions of "B(x,y)B(x+y,z)=B(z,x)B(x+z,y)"
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(Created page with "==Theorem== The following formula holds: $$B(x,y)B(x+y,z)=B(z,x)B(x+z,y),$$ where $B$ denotes the beta function. ==Proof== ==References== * {{BookReference|Higher Transc...") |
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Revision as of 23:01, 24 June 2017
Theorem
The following formula holds: $$B(x,y)B(x+y,z)=B(z,x)B(x+z,y),$$ where $B$ denotes the beta function.
Proof
References
- 1953: Harry Bateman: Higher Transcendental Functions Volume I ... (previous) ... (next): $\S 1.5 (7)$
