Difference between revisions of "X/(1+x) less than log(1+x)"
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Latest revision as of 19:49, 25 June 2017
Theorem
The following formula holds for $x>-1$: $$\dfrac{x}{1+x} < \log(1+x),$$ where $\log$ denotes the logarithm.
Proof
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): $4.1.33$
