Difference between revisions of "Laguerre L"
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Revision as of 14:08, 15 March 2018
The Laguerre polynomial of order $n$, $L_n$, is given by $$L_n(x) = \displaystyle\sum_{k=0}^n \dfrac{(-1)^kn!}{(n-k)!(k!)^2}x^k.$$
The first few Laguerre polynomials are given by $$\begin{array}{ll} L_0(x) &= 1 \\ L_1(x) &= -x+1 \\ L_2(x) &= \dfrac{1}{2}(x^2-4x+2) \\ L_3(x) &= \dfrac{1}{6}(-x^3+9x^2-18x+6) \\ L_4(x) &= \dfrac{1}{24}(x^4-16x^3+72x^2-96x+24)\\ \vdots \end{array}$$
Graph of $L_n$ for $n=0,1,2,\ldots,5$ on $[-3,10]$.
Properties
Generating function for Laguerre L
L n(x)=(e^x/n!)d^n/dx^n(x^n e^(-x))
Theorem (Orthogonality): The following formula holds: $$\displaystyle\int_0^{\infty} e^{-x}L_n(x)L_m(x)dx = \delta_{nm},$$ where $\delta_{mn}=0$ when $m\neq n$ and $\delta_{mn}=1$ when $m=n$.
Proof: █
Theorem: The following formula holds: $$(n+1)L_{n+1}(x)=(2n+1-x)L_n(x)-nL_{n-1}(x).$$
Proof: █
Theorem: The following formula holds: $$xL_n'(x)=nL_n(x)-nL_{n-1}(x).$$
Proof: █
Theorem: The following formula holds: $$L_n'(x)=-\displaystyle\sum_{k=0}^{n-1} L_k(x).$$
Proof: █
See also
References
- 1968: W.W. Bell: Special Functions for Scientists and Engineers ... (previous) ... (next): $(6.3)$
