Weierstrass factorization of cosh
From specialfunctionswiki
Revision as of 01:51, 17 April 2015 by Tom (talk | contribs) (Created page with "<div class="toccolours mw-collapsible mw-collapsed"> <strong>Theorem:</strong> The Weierstrass factorization of $\cosh(x)$ i...")
Theorem: The Weierstrass factorization of $\cosh(x)$ is $$\cosh x = \displaystyle\prod_{k=1}^{\infty} 1 + \dfrac{4x^2}{(2k-1)^2\pi^2}.$$
Proof: █
