Li 2(1)=pi^2/6
From specialfunctionswiki
Revision as of 00:02, 4 June 2016 by Tom (talk | contribs) (Created page with "==Theorem== The following formula holds: $$\mathrm{Li}_2(1) = \dfrac{\pi^2}{6},$$ where $\mathrm{Li}$ denotes the dilogarithm and $\pi$ denotes pi. ==References== {{B...")
Theorem
The following formula holds: $$\mathrm{Li}_2(1) = \dfrac{\pi^2}{6},$$ where $\mathrm{Li}$ denotes the dilogarithm and $\pi$ denotes pi.
References
1926: Leonard Lewin: Polylogarithms and Associated Functions (2nd ed.) ... (previous): (1.9)
