Q-number when a=n is a natural number
From specialfunctionswiki
Theorem
The following formula holds for $n \in \{1,2,\ldots\}$ and $q \in \mathbb{C} \setminus \{0,1\}$: $$[n]_q=\displaystyle\sum_{k=1}^n q^{k-1}.$$
Proof
References
- 2012: Thomas Ernst: A Comprehensive Treatment of q-Calculus ... (previous) ... (next): (6.2)