Q-difference equation for q-exponential E sub q
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Theorem
The following formula holds: $$D_q E_q(az) = aE_q(az),$$ where $D_q$ is the $q$-difference operator and $E_q$ is the $q$-exponential $E_q$.
Proof
References
- 2012: Thomas Ernst: A Comprehensive Treatment of q-Calculus ... (previous): (6.152)
