Difference between revisions of "Exponential integral E"

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=Properties=
 
=Properties=
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[[Relationship between the exponential integral and upper incomplete gamma function]]
<strong>Theorem:</strong> The exponential integral $E_1$ has series representation
 
$$E_1(z)=-\gamma-\log z - \displaystyle\sum_{k=1}^{\infty} \dfrac{(-1)^kz^k}{kk!}, \quad |\mathrm{arg}(z)|<\pi,$$
 
where $\gamma$ denotes the [[Euler-Mascheroni constant]].
 
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<strong>Proof:</strong> █
 
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<strong>Theorem (Symmetry):</strong> The following symmetry relation holds:
 
$$E_n(\overline{z})=\overline{E_n(z)}.$$
 
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<strong>Proof:</strong> █
 
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<strong>Theorem (Recurrence):</strong> The following recurrence holds:
 
$$E_{n+1}(z) = \dfrac{1}{n}[e^{-z}-zE_n(z)];(n=1,2,3,\ldots).$$
 
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<strong>Proof:</strong> █
 
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<strong>Theorem ([[Continued fraction]]):</strong> The following formula holds:
 
$$E_n(z)=e^{-z} \left( \dfrac{1}{z+} \dfrac{n}{1+} \dfrac{1}{z+} \dfrac{n+1}{1+} \dfrac{2}{z+} \ldots \right); |\mathrm{arg} z|<\pi.$$
 
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<strong>Proof:</strong> █
 
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<strong>Theorem:</strong> The following value is known:
 
$$E_n(0)=\dfrac{1}{n-1}; n>1.$$
 
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<strong>Proof:</strong> █
 
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<strong>Theorem:</strong> The following closed form expression is known:
 
$$E_0(z)=\dfrac{e^{-z}}{z}.$$
 
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<strong>Proof:</strong> █
 
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<strong>Theorem (Derivative):</strong> $$\dfrac{d}{dz} E_n(z) = -E_{n-1}(z); n=1,2,3,\ldots$$
 
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<strong>Proof:</strong> █
 
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{{:Relationship between the exponential integral and upper incomplete gamma function}}
 
  
 
=Videos=
 
=Videos=

Revision as of 08:04, 8 June 2016

The exponential integral functions $E_n$ are defined by $$E_1(z) = \displaystyle\int_1^{\infty} \dfrac{e^{-t}}{t} \mathrm{d}t, \quad \left|\mathrm{arg \hspace{2pt}}z\right|<\pi,$$ and $$E_n(z)=\displaystyle\int_1^{\infty} \dfrac{e^{-zt}}{t^n} \mathrm{d}t.$$

Properties

Relationship between the exponential integral and upper incomplete gamma function

Videos

Laplace transform of exponential integral

References

Exponential Integral and Related Functions

<center>$\ast$-integral functions
</center>