Difference between revisions of "Q-difference equation for q-exponential E sub q"
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==References== | ==References== | ||
| − | * {{BookReference|A Comprehensive Treatment of q-Calculus|2012|Thomas Ernst|prev=Meromorphic continuation of q-exponential E sub q|next=Q-exponential E sub 1/q}}: (6.152) | + | * {{BookReference|A Comprehensive Treatment of q-Calculus|2012|Thomas Ernst|prev=Meromorphic continuation of q-exponential E sub q|next=Q-exponential E sub 1/q}}: ($6.152$) |
[[Category:Theorem]] | [[Category:Theorem]] | ||
[[Category:Unproven]] | [[Category:Unproven]] | ||
Latest revision as of 07:40, 18 December 2016
Theorem
The following formula holds: $$D_q E_q(az) = aE_q(az),$$ where $D_q$ is the $q$-difference operator and $E_q$ is the $q$-exponential $E_q$.
Proof
References
- 2012: Thomas Ernst: A Comprehensive Treatment of q-Calculus ... (previous) ... (next): ($6.152$)
