Recurrence relation of exponential integral E
From specialfunctionswiki
Revision as of 00:23, 8 August 2016 by Tom (talk | contribs) (Created page with "==Theorem== The following formula holds for $n=1,2,3,\ldots$: $$E_{n+1}(z)=\dfrac{e^{-z}-zE_n(z)}{n},$$ where $E_n$ denotes the exponential integral E. ==Proof== ==Refer...")
Theorem
The following formula holds for $n=1,2,3,\ldots$: $$E_{n+1}(z)=\dfrac{e^{-z}-zE_n(z)}{n},$$ where $E_n$ denotes the exponential integral E.
Proof
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): $5.1.14$
