Difference between revisions of "Derivative of secant"
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==Theorem== | ==Theorem== | ||
The following formula holds: | The following formula holds: | ||
− | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \ | + | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \sec(z)=\tan(z)\sec(z),$$ |
− | where $\ | + | where $\sec$ denotes the [[secant]] and $\cot$ denotes the [[cotangent]]. |
==Proof== | ==Proof== | ||
+ | From the definition of secant, | ||
+ | $$\sec(z) = \dfrac{1}{\cos(z)},$$ | ||
+ | and so using the [[quotient rule]], the [[derivative of cosine]], and the definition of [[tangent]], | ||
+ | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \sec(z) = \dfrac{\mathrm{d}}{\mathrm{d}z} \dfrac{1}{\cos(z)} = \dfrac{\sin(z)}{\cos^2(z)}=\tan(z)\sec(z),$$ | ||
+ | as was to be shown. $\blacksquare$ | ||
==References== | ==References== | ||
+ | *{{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Derivative of cosecant|next=Derivative of cotangent}}: $4.3.109$ | ||
[[Category:Theorem]] | [[Category:Theorem]] | ||
− | [[Category: | + | [[Category:Proven]] |
Latest revision as of 00:34, 26 April 2017
Theorem
The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}z} \sec(z)=\tan(z)\sec(z),$$ where $\sec$ denotes the secant and $\cot$ denotes the cotangent.
Proof
From the definition of secant, $$\sec(z) = \dfrac{1}{\cos(z)},$$ and so using the quotient rule, the derivative of cosine, and the definition of tangent, $$\dfrac{\mathrm{d}}{\mathrm{d}z} \sec(z) = \dfrac{\mathrm{d}}{\mathrm{d}z} \dfrac{1}{\cos(z)} = \dfrac{\sin(z)}{\cos^2(z)}=\tan(z)\sec(z),$$ as was to be shown. $\blacksquare$
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): $4.3.109$