Difference between revisions of "Log 10(z)=log 10(e)log(z)"
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Latest revision as of 19:29, 25 June 2017
Theorem
The following formula holds: $$\log_{10}(z)=\log_{10}(e)\log(z),$$ where $\log_{10}$ denotes logarithm base a, $e$ denotes e, and $\log$ denotes logarithm.
Proof
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): $4.1.22$
