Halving identity for cosh
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Theorem
The following formula holds: $$\cosh \left( \dfrac{z}{2} \right) = \sqrt{ \dfrac{\cosh(z)+1}{2} },$$ where $\cosh$ denotes hyperbolic cosine.
Proof
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): $4.5.29$
