Pages that link to "2F1(1/2,1;3/2;z^2)=log((1+z)/(1-z))/(2z)"

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The following pages link to 2F1(1/2,1;3/2;z^2)=log((1+z)/(1-z))/(2z):

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• Book:Milton Abramowitz/Handbook of mathematical functions ‎ (← links)
• Hypergeometric 2F1 ‎ (← links)
• 2F1(1,1;2;z)=-log(1-z)/z ‎ (← links)
• 2F1(1/2,1;3/2;-z^2)=arctan(z)/z ‎ (← links)

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