Difference between revisions of "Logarithm base a"
From specialfunctionswiki
(Created page with "The logarithm with base $a$, $\log_a$, is defined by $$\log_a(z)=\dfrac{\log(z)}{\log(a)},$$ where $\log$ denotes the logarithm. =Properties= =References= * {{BookRefere...") |
|||
| (6 intermediate revisions by the same user not shown) | |||
| Line 4: | Line 4: | ||
=Properties= | =Properties= | ||
| + | [[Log base a in terms of logarithm base b]]<br /> | ||
| + | [[Log a(z)=1/log b(a)]]<br /> | ||
| + | [[Log e(z)=log(z)]]<br /> | ||
| + | [[Log 10(z)=log(z)/log(10)]]<br /> | ||
| + | [[Log 10(z)=log 10(e)log(z)]]<br /> | ||
| + | [[Log(z)=log(10)log 10(z)]]<br /> | ||
| + | |||
| + | =See also= | ||
| + | [[Logarithm]]<br /> | ||
| + | [[Logarithm (multivalued)]]<br /> | ||
=References= | =References= | ||
Latest revision as of 19:36, 25 June 2017
The logarithm with base $a$, $\log_a$, is defined by $$\log_a(z)=\dfrac{\log(z)}{\log(a)},$$ where $\log$ denotes the logarithm.
Properties
Log base a in terms of logarithm base b
Log a(z)=1/log b(a)
Log e(z)=log(z)
Log 10(z)=log(z)/log(10)
Log 10(z)=log 10(e)log(z)
Log(z)=log(10)log 10(z)
See also
Logarithm
Logarithm (multivalued)
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): $4.1.18$
